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				+#ifndef __CDPF_HPP__ 
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				+#define __CDPF_HPP__ 
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				+#include <tuple> 
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				+#include "types.hpp" 
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				+#include "dpf.hpp" 
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				+ 
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				+// DPFs for doing comparisons of (typically) 64-bit values. We use the 
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				+// technique from: 
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				+// 
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				+// Kyle Storrier, Adithya Vadapalli, Allan Lyons, Ryan Henry. 
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				+// Grotto: Screaming fast (2 + 1)-PC for Z_{2^n} via (2, 2)-DPFs 
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				+// 
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				+// The idea is that we have a pair of DPFs with 64-bit inputs and a 
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				+// single-bit output.  The outputs of these DPFs are the same for all 
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				+// 64-bit inputs x except for one special one (target), where they're 
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				+// different, but if you have just one of the DPFs, you can't tell what 
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				+// the value of target is.  The construction of the DPF is a binary 
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				+// tree, where each interior node has a 128-bit value, the low bit of 
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				+// which is the "flag" bit.  The invariant is that if a node is on the 
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				+// path leading to the target, then not only are the two 128-bit values 
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				+// on the node (one from each DPF) different, but their flag (low) bits 
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				+// are themselves different, and if a node is not on the path leading to 
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				+// the target, then its 128-bit value is the _same_ in the two DPFs. 
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				+// Each DPF also comes with an additive share (target0 or target1) of 
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				+// the random target value. 
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				+// 
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				+// Given additive shares x0 and x1 of x, two parties can determine 
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				+// bitwise shares of whether x>0 as follows: exchange (target0-x0) and 
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				+// (target1-x1); both sides add them to produce S = (target-x). 
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				+// Notionally consider (but do not actually construct) a bit vector V of 
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				+// length 2^64 with 1s at positions S+1, S+2, ..., S+(2^63-1), wrapping 
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				+// around if the indices exceed 2^64-1.  Now consider (but again do not 
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				+// actually do) the dot product of V with the full evaluation of the 
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				+// DPFs.  The full evaluations of the DPFs are random bit vectors that 
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				+// differ in only the bit at position target, so the two dot products 
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				+// (which are each a single bit) will be a bitwise shraring of the value 
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				+// of V at position target.  Note that if V[target] = 1, then target = 
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				+// S+k for some 1 <= k <= 2^63-1, then since target = S+x, we have that 
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				+// x = k is in that same range; i.e. x>0 as a 64-bit signed integer (and 
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				+// similarly if V[target] = 0, then x <= 0. 
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				+// 
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				+// So far, this is all standard, and for DPFs of smaller depth, this is 
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				+// the same technique we're doing for RDPFs.  But we can't do it for 
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				+// vectors of size 2^64; that's too big.  Even for 2^32 it would be 
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				+// annoying.  The observation made in the Grotto paper is that you can 
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				+// actually compute this bit sharing in time linear in the *depth* of 
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				+// the DPF (that is, logarithmic in the length of V), for some kinds of 
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				+// vectors V, including the "single block of 1s" one described above. 
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				+// 
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				+// The key insight is that if you look at any _interior_ node of the 
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				+// tree, the corresponding nodes on the two DPFs will be a bit sharing 
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				+// of the sum of all the leaves in the subtree rooted at that interior 
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				+// node: 0 if target is not in that subtree, and 1 if it is.  So you 
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				+// just have to find the minimal set of interior nodes such that the 
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				+// leaves of the subtrees rooted at those nodes is exactly the block of 
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				+// 1s in V, and then each party adds up the flag bits of those leaves. 
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				+// The result is a bit sharing of 1 if V[target]=1 and 0 if V[target]=0; 
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				+// that is, it is a bit sharing of V[target], and so (as above) of the 
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				+// result of the comparison [x>0].  You can also find and evaluate the 
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				+// flag bits of this minimal set in time and memory linear in the depth 
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				+// of the DPF. 
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				+// 
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				+// So at the end, we've computed a bit sharing of [x>0] with local 
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				+// computation linear in the depth of the DPF (concretely, fewer than 
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				+// 200 AES operations), and only a *single word* of communication in 
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				+// each direction (exchanging the target{i}-x{i} values).  Of course, 
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				+// this assumes you have one pair of these DPFs lying around, and you 
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				+// have to use a fresh pair with a fresh random target value for each 
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				+// comparison, since revealing target-x for two different x's but the 
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				+// same target leaks the difference of the x's. But in the 3-party 
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				+// setting (or even the 2+1-party setting), you can just have the server 
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				+// precompute a bunch of these pairs in advance, and hand bunches of the 
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				+// first item in each pair to player 0 and the second item in each pair 
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				+// to player 1, at preprocessing time (a single message from the server 
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				+// to each of player 0 and player 1), and these DPFs are very fast to 
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				+// compute, and very small (< 1KB each) to transmit and store. 
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				+ 
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				+// See also dpf.hpp for the differences between these DPFs and the ones 
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				+// we use for oblivious random access to memory. 
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				+ 
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				+struct CDPF : public DPF { 
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				+    // Additive and XOR shares of the target value 
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				+    RegAS as_target; 
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				+    RegXS xs_target; 
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				+    // The extra correction word we'll need for the right child at the 
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				+    // final leaf layer; this is needed because we're making the tree 7 
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				+    // layers shorter than you would naively expect (depth 57 instead of 
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				+    // 64), and having the 128-bit labels on the leaf nodes directly 
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				+    // represent the 128 bits that would have come out of the subtree of 
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				+    // a (notional) depth-64 tree rooted at that depth-57 node. 
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				+    DPFnode leaf_cw; 
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				+ 
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				+    // Generate a pair of CDPFs with the given target value 
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				+    static std::tuple<CDPF,CDPF> generate(value_t target); 
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				+ 
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				+    // Generate a pair of CDPFs with a random target value 
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				+    static std::tuple<CDPF,CDPF> generate(); 
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				+}; 
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				+ 
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				+#endif 
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